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15a^2-43a+30=0
a = 15; b = -43; c = +30;
Δ = b2-4ac
Δ = -432-4·15·30
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-7}{2*15}=\frac{36}{30} =1+1/5 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+7}{2*15}=\frac{50}{30} =1+2/3 $
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